|CSIR NET 2020 : Information Bulletin, NTA CSIR NET, JRF June Exam Online Form 2020 – CSIR NET June Recruitment 2020, National Eligibility Test (NET) 2020 Dates, Eligibility Criteria, Apply Online Application, Registration Process and Exam Fee Available at Official Website https://csirnet.nta.nic.in/.|
|Published on : 03/17/2020||Latest Updated On : 03/17/2020|
CSIR NET 2020 Notification
|Date : 2020-03-16
|NTA CSIR NET 2020 June Online Form|
Short Info: Council of Scientific & Industrial Research (CSIR) has issued a notification of UGC-NET for Junior Research Fellowship (JRF) & Lecturership (LS) June 2020.
CSIR NET 2020 Exam will be conducted by NTA in 5 subjects of Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences, Physical Sciences at selected Examination Centers spread across the country for the post of Junior Research Fellowship (JRF) and for Lectureship/Assistant Professor. The Council of Scientific & Industrial Research (CSIR) has entrusted the responsibility of conducting CSIR-NET to the NTA established by Ministry of Human Resource Development (MHRD), Government of India (GOI).
All Candidates who are willing to apply online application then download official notification and read all eligibility criteria and Selection process carefully. We will provide short information about “CSIR NET 2020” like Eligibility Criteria, Age Limit, Application Fee, Selection process and more.
|Joint CSIR-UGC NET Exam June 2020|
|Joint CSIR-UGC NET Examination would be conducted by NTA on Sunday, 21 June 2020 for determining the eligibility of Indian Nationals for the award of Junior Research Fellowships (JRF) and for determining eligibility for Lectureship (LS)/Assistant Professor in certain subject areas falling under the faculty of Science & Technology. Joint CSIR-UGC NET June, 2020 shall be conducted by NTA on 21 June, 2020 in the enlisted subjects given below based on syllabus (available at www.csirhrdg.res.in ), at selected Cities of Examination centres spread across the country.
CSIR-UGC NET Exam for Science stream is conducted by CSIR in the following areas: –
|CSIR NET 2020 : Overview|
|Conduction Body||National Testing Agency (NTA)|
|NTA Official Portal||https://nta.nic.in/|
|Name of Organisation||Council of Scientific & Industrial Research (CSIR)|
|UGC Official Website||https://www.csir.res.in/|
|Name of the Examination||National Eligibility Test (CSIR-UGC NET) JUNE 2020|
|NTA NET Official Website||https://csirnet.nta.nic.in/|
|Exam Level||National Level Exam|
|Exam Type||Eligibility Test|
|Date of Examination||June 21, 2020|
|Mode of Application||Online|
|Subjects||Chemical Sciences, Earth, Atmospheric, Ocean and Planetary Sciences, Life Sciences, Mathematical Sciences, Physical Sciences.|
|Event||Dates & Time|
|CSIR NET Notification Release Date||by 16th March 2020|
|Release of Application form||16th March 2020|
|Last date to Submit CSIR NET Application||15th April 2020 (upto 11:50 pm)|
|Last date to Pay Fee||16th April 2020 (upto 11:50 pm)|
|Correction in particulars of Application Form on website only||18th April to 24rd Aapril 2020|
|Downloading of Admit Cards from NTA website||15th May, 2020|
|CSIR NET 2020 Exam Dates||21th June 2020|
|Duration of UGC Exam||180 minutes (03 hours)
No break between Paper 1 & Paper 2
|Timing of Examination||First Shift: 9.30 am to 12.30 pm
Second Shift: 02.30 pm to 05.30 pm
|CSIR NET 2020 Result Date||by 5th July 2020|
|Release of Score on NTA website||By 2nd Week of July 2020|
|Apply Online||Click Here|
|Information Bulletin||Click Here|
|Public Notice||HINDI | ENGLISH|
|Official Website||Click Here|
|CSIR NET 2020 Application Fee|
|OBc (NCL)||Rs 500/-|
|Fee can be paid through Credit Card/ Debit Card/ Net Banking|
How to Apply Online
|Steps to Apply CSIR NET Online Application –|
|Fill Application Form UGC-NET JUNE 2020 – NTA releases CSIR NET 2020 application form through the online process. Get the Step by Step guide to fill CSIR NET application form 2020 below:
Step 1st : Visit the official website for CSIR NET, https://csirnet.nta.nic.in/ or click on the direct link provided above.
Step 2nd : Click on ‘fill online application form’ tab present at the bottom.
Step 3rd : Now, click on ‘new registration’ button.
Step 4th : Click on ‘proceed to apply online’ after reading the important instructions.
Step 5th : Enter the details asked in the registration page and click on the ‘submit’ button.
Step 6th : Now, proceed with CSIR NET application form 2020. Enter the details asked in the application form – personal details, educational qualification. Hit the ‘submit’ button.
Step 7th : Upload the images of photograph and signature as per specifications.
Payment of application fee
Step 8th : Last Step is to pay CSIR NET online application fee. Take print of the confirmation page and keep it safe for future reference.
|Necessary Documents to fill CSIR NET 2020 Application Form|
|Candidates have to use the below given documents to fill in the application form of CSIR NET 2020. The documents below are to be used for reference and some are to be uploaded in the application form.
Before beginning the process of filling the form, please keep the following information ready with you:
Documents to upload in the online application form:
|Scanned Image Specification*|
|Images to Upload||Format/ File Size|
|Photo||JPG/JPEG/ 10 KB – 200 KB|
|Signature||JPG/JPEG/ 04 KB to 30 KB|
Note: Passport size photograph is to be used for uploading on Online Application Form and also for pasting on Attendance Sheet at the examination centre.
CSIR NET 2020 Eligibility Criteria
|To candidates holding BS-4 years program/BE/B. Tech/B. Pharma/MBBS/ Integrated BS-MS/M.Sc. or Equivalent degree/BSc (Hons) or equivalent degree holders or students enrolled in integrated MS-Ph.D program with at least 55% marks for General & OBC (50% for SC/ST candidates, Physically and Visually handicapped candidates) after qualifying the National Eligibility Test ( NET) conducted by CSIR twice a year June and December.
Candidates with bachelor’s degree, whether Science, engineering or any other discipline, will be eligible for fellowship only after getting registered/enrolled for Ph.D/integrated Ph.D. programme within the validity period of two years.
Candidate enrolled for M.Sc. or having completed 10+2+3 years of the above qualifying examination are also eligible to apply in the above subject under the Result Awaited (RA) category.
|For JRF||Not more than 28 years as on 01-01-2020|
|For LS/ Assistant Professorship||There is no upper age limit.|
|Relaxation: Relaxed upto 5 years in the case of candidates belonging to Schedule Castes/Schedule Tribes/, Physically Handicapped/Visually Handicapped and female applicants whereas 3 years in case of OBCs (Non-creamy layer candidates).
CSIR NET 2020
|What is CSIR NET ?|
|The Council of Scientific and Industrial Research (CSIR) has entrusted the responsibility of conducting CSIR-UGC NET in CBT mode to NTA. CSIR-UGC NET is a test being conducted to determine the eligibility ‘for Junior Research Fellowship (JRF) and for Lectureship/Assistant Professor’ in Indian universities and colleges subject to fulfilling the eligibility criteria laid down by UGC. Online applications for JRF/NET are invited twice a year on all India basis through Press Notification of CSIR-UGC NET for JRF and LS/AP.
CSIR and UGC provide Research Fellowships for training in methods of research under expert guidance of faculty members/scientists working in University Department/ National Laboratories and Institutions in various fields of Science. CSIR-UGC NET Fellowships are tenable in Universities/IITs/Post Graduate Colleges/Govt. Research Establishments including those of the CSIR, Research & Development establishments of recognized public or private sector industrial firms and other recognized institutions. Only bonafide Indian Citizens are eligible for the test. CSIR-UGC NET Fellowship is tenable in India. The programme is aimed at National Science & Technology Human Resource Development.
|National Eligibility Test (NET)|
|National Eligibility Test is conducted twice in a year for selection of deserving candidates for the posts of Assistant Professor and Junior Research Fellowship (JRF) in Indian Govt. Universities and Colleges. NTA CSIR NET exam is conducted in the month of June & December every year. As per a recent announcement by the HRD Ministry, the examination will now be conducted by National Testing Agency (NTA). In fact, CSIR NET 2020 June session would be the third exam of the agency (NTA).|
|National Testing Agency (NTA)|
|The Ministry of Human Resource Development (MHRD), Government of India (GOI), has established National Testing Agency (NTA) as an independent, autonomous and self- sustained premier organization under the Societies Registration Act, 1860, registered as a self-reliant and self-sustained premier testing organization.|
|Junior Research Fellowship Stipend|
|The stipend of a JRF selected through CSIR- National Eligibility Test (NET) will be Rs.31,000/- p.m for the first two years. In addition, annual contingent grant of Rs.20,000/- per Fellow will be provided to the University / Institution. The Fellowship will be governed by terms and conditions of CSIR, UGC or Research Scheme, as applicable.|
CSIR NET 2020 Exam Pattern
|CSIR NET 2020 Exam Pattern & Marking Scheme|
|Mode of Exam||Computer based test (CBT)|
|Duration of examination||150 minutes (1 hour 30 minutes)|
|Type of questions||Multiple Choice Type Questions|
|Number of papers||02 papers|
|Number of questions||Varies for different subjects|
|Maximum marks||200 marks|
|Language||English and Hindi languages.|
|Sections||Question paper consists of three parts A, B and C.|
|For correct answer||PART A, B : +2 marks, PART C: +4 Marks|
|For incorrect answer||(-25%) Negative marking for wrong answers.|
|Distribution of questions|
|Part ‘A’ shall be common to all subjects. This part shall be a test containing a maximum of 20 questions of General Aptitude. The candidates shall be required to answer any 15 questions of two marks each. The total marks allocated to this section shall be 30 out of 200
Part ‘B’ shall contain subject-related conventional MCQs. The total marks allocated to this section shall be 70 out of 200. The maximum number of questions to be attempted shall be in the range of 20-35.
Part ‘C’ shall contain higher value questions that may test the candidate’s knowledge of scientific concepts and/or application of the scientific concepts. The questions shall be of analytical nature where a candidate is expected to apply the scientific knowledge to arrive at the solution to the given scientific problem. The total marks allocated to this section shall be 100 out of 200.
Check out the detailed examination pattern of CSIR NET 2020 for all the subjects below.
CSIR NET Cut Offs
|CSIR NET Cut Off & Qualifying Marks|
|CSIR NET 2020 Cut Off will be published online by the authority after the entrance test. Separate category wise and subject wise merit list will be drawn for the students successfully securing the cut off marks.
Candidates must have score the minimum qualifying marks as indicated below to be eligible for CSIR NET 2020.
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